Before writing the program for finding Leap year, I just want to give you a brief history about the leap year and what it is.

It takes the Earth approximately 365 days, 5 hours, 48 minutes, and 46 seconds to circle once around the Sun. Leap Years are needed to keep our calendar alignment with the Earth's revolutions around the sun. So if we didn't add a day on February 29 nearly every 4 years, we would lose almost six hours off our calendar every year. After only 100 years, our calendar would be off by approximately 24 days!

To determine whether a year is a leap year or not , follow the below mentioned algorithm

**Algorithm**

1. If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.

2. If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.

3. If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.

4. The year is a leap year (it has 366 days).

5. The year is not a leap year (it has 365 days).

If the value in cell A1 is this The formula returns

----------------------------------------------------------

1992 Leap Year

2000 Leap Year

1900 NOT a Leap Year

**Program to determine whether the year is a leap year or not**

int inputYear;

printf("Please Enter Year");

scanf("%d",&inputYear);

if(inputYear%4 == 0)

if(inputYear%100 == 0 )

{

if(inputYear%400
== 0)

printf("%d
is a Leap Year",inputYear);

else

printf("%d
is not Leap Year",inputYear);}

else

{

printf("%d is Leap
Year",inputYear);

}

else

{

printf("%d is not Leap
Year",inputYear);

}

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